Cara menggunakan pmf python pandas

By On Friday, October 7th, 2022 Categories : Tanya Jawab

Cara menggunakan pmf python pandas – Hi tante dan om semua, Thanks dah mau datang ke blog ini. Malam ini, kami dari web akan share tanya jawab yang mantap yang menunjukkan pada anda mengenai Cara menggunakan pmf python pandas. Sebaiknya tante dan om melihat di bawah ini:

scipy.stats.hypergeom=<scipy.stats._discrete_distns.hypergeom_gen object>[source]#

A hypergeometric discrete random variable.

The hypergeometric distribution models drawing objects from a bin. M is the total number of objects, n is
total number of Type I objects. The random variate represents the number of Type I objects in N drawn without replacement from the total population.

As an instance of the rv_discrete class,
hypergeom object inherits from it a collection of generic methods (see below for the full list), and completes them with details specific for this particular distribution.


The symbols used to denote the shape parameters (M, n, and N) are not universally accepted. See the Examples for a
clarification of the definitions used here.

The probability mass function is defined as,

\[p(k, M, n, N) = \frac\binomnk \binomM – nN – k

for \(k \in [\max(0, N – M + n), \min(n, N)]\), where the binomial coefficients are defined as,

\[\binomnk \equiv \fracn!k! (n – k)!.\]

The probability mass function above is defined in the “standardized” form. To shift distribution use the loc parameter. Specifically,
hypergeom.pmf(k, M, n, N, loc) is identically equivalent to hypergeom.pmf(k - loc, M, n, N).


>>> from scipy.stats import hypergeom
>>> import matplotlib.pyplot as plt

Suppose we have a collection of 20 animals, of which 7 are dogs. Then if we want to know the probability of finding a given number of dogs if we choose at random 12 of the 20 animals, we can initialize a frozen distribution and plot the probability mass function:

>>> [M, n, N] = [20, 7, 12]
>>> rv = hypergeom(M, n, N)
>>> x = np.arange(0, n+1)
>>> pmf_dogs = rv.pmf(x)
>>> fig = plt.figure()
>>> ax = fig.add_subplot(111)
>>> ax.plot(x, pmf_dogs, 'bo')
>>> ax.vlines(x, 0, pmf_dogs, lw=2)
>>> ax.set_xlabel('# of dogs in our group of chosen animals')
>>> ax.set_ylabel('hypergeom PMF')

Instead of using a frozen distribution we can also use hypergeom methods directly. To for example obtain the cumulative distribution function, use:

>>> prb = hypergeom.cdf(x, M, n, N)

And to generate
random numbers:

>>> R = hypergeom.rvs(M, n, N, size=10)


rvs(M, n, N, loc=0, size=1, random_state=None)

Random variates.

pmf(k, M, n, N, loc=0)

Probability mass function.

logpmf(k, M, n, N, loc=0)

Log of the probability mass function.

cdf(k, M, n, N, loc=0)

Cumulative distribution function.

logcdf(k, M, n, N, loc=0)

Log of the cumulative distribution function.

sf(k, M, n, N, loc=0)

Survival function (also defined as 1 - cdf, but sf is sometimes more accurate).

logsf(k, M, n, N, loc=0)

Log of the survival function.

ppf(q, M, n, N, loc=0)

Percent point function (inverse of cdf — percentiles).

isf(q, M, n, N, loc=0)

Inverse survival function (inverse of sf).

stats(M, n, N, loc=0, moments=’mv’)

Mean(‘m’), variance(‘v’), skew(‘s’), and/or kurtosis(‘k’).

entropy(M, n, N, loc=0)

(Differential) entropy of the RV.

expect(func, args=(M, n, N), loc=0, lb=None, ub=None, conditional=False)

Expected value of a function (of one argument) with respect to the distribution.

median(M, n, N, loc=0)

Median of the distribution.

mean(M, n, N, loc=0)

Mean of the distribution.

var(M, n, N, loc=0)

Variance of the distribution.

std(M, n, N, loc=0)

Standard deviation of the distribution.

interval(confidence, M, n, N, loc=0)

Confidence interval with equal areas around the median.

Cara menggunakan pmf python pandas | admin | 4.5
shopee flash sale gratis ongkir